1/2(3x-10)=-13+x-16

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Solution for 1/2(3x-10)=-13+x-16 equation: 



1/2(3x-10)=-13+x-16

We move all terms to the left:

1/2(3x-10)-(-13+x-16)=0



Domain of the equation: 2(3x-10)!=0

x∈R



We add all the numbers together, and all the variables

1/2(3x-10)-(x-29)=0

We get rid of parentheses

1/2(3x-10)-x+29=0

We multiply all the terms by the denominator


-x*2(3x-10)+29*2(3x-10)+1=0

Wy multiply elements

-2x^2(3+58x(3+1=0

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