1/2(3x+5)-3/2=1/4(2x+12)

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Solution for 1/2(3x+5)-3/2=1/4(2x+12) equation: 



1/2(3x+5)-3/2=1/4(2x+12)

We move all terms to the left:

1/2(3x+5)-3/2-(1/4(2x+12))=0



Domain of the equation: 2(3x+5)!=0

x∈R





Domain of the equation: 4(2x+12))!=0

x∈R



We calculate fractions


(4x2/(2(3x+5)*4(2x+12))*2)+(-(1*2(3x+5)*2)/(2(3x+5)*4(2x+12))*2)+(-12x2/(2(3x+5)*4(2x+12))*2)=0



We calculate terms in parentheses: +(4x2/(2(3x+5)*4(2x+12))*2), so:

4x2/(2(3x+5)*4(2x+12))*2

We multiply all the terms by the denominator


4x2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)





We calculate terms in parentheses: +(-(1*2(3x+5)*2)/(2(3x+5)*4(2x+12))*2), so:

-(1*2(3x+5)*2)/(2(3x+5)*4(2x+12))*2

We multiply all the terms by the denominator


-(1*2(3x+5)*2)



We calculate terms in parentheses: -(1*2(3x+5)*2), so:

1*2(3x+5)*2

Wy multiply elements

4x(3

Back to the equation:

-(4x(3)



Back to the equation:

+(-(4x3)





We calculate terms in parentheses: +(-12x2/(2(3x+5)*4(2x+12))*2), so:

-12x2/(2(3x+5)*4(2x+12))*2

We multiply all the terms by the denominator


-12x2

We add all the numbers together, and all the variables

-12x^2

Back to the equation:

+(-12x^2)

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