1/2(3-t)=1/3(t+2)

Solution for 1/2(3-t)=1/3(t+2) equation:

1/2(3-t)=1/3(t+2)

We move all terms to the left:

1/2(3-t)-(1/3(t+2))=0


Domain of the equation: 2(3-t)!=0

t∈R



Domain of the equation: 3(t+2))!=0

t∈R


We add all the numbers together, and all the variables

1/2(-1t+3)-(1/3(t+2))=0

We calculate fractions


(3tt/(2(-1t+3)*3(t+2)))+(-2t0/(2(-1t+3)*3(t+2)))=0


We calculate terms in parentheses: +(3tt/(2(-1t+3)*3(t+2))), so:

3tt/(2(-1t+3)*3(t+2))

We multiply all the terms by the denominator


3tt

Back to the equation:

+(3tt)



We calculate terms in parentheses: +(-2t0/(2(-1t+3)*3(t+2))), so:

-2t0/(2(-1t+3)*3(t+2))

We multiply all the terms by the denominator


-2t0

We add all the numbers together, and all the variables

-2t

Back to the equation:

+(-2t)


We get rid of parentheses

3tt-2t=0

We add all the numbers together, and all the variables

-2t+3tt=0