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1/2(2y+10+6y)=3y+5
We move all terms to the left:
1/2(2y+10+6y)-(3y+5)=0
Domain of the equation: 2(2y+10+6y)!=0We add all the numbers together, and all the variables
y∈R
1/2(8y+10)-(3y+5)=0
We get rid of parentheses
1/2(8y+10)-3y-5=0
We multiply all the terms by the denominator
-3y*2(8y+10)-5*2(8y+10)+1=0
Wy multiply elements
-6y^2(8-10y(8+1=0
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