1/2(2x-8)=1/2(8x+10)

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Solution for 1/2(2x-8)=1/2(8x+10) equation: 



1/2(2x-8)=1/2(8x+10)

We move all terms to the left:

1/2(2x-8)-(1/2(8x+10))=0



Domain of the equation: 2(2x-8)!=0

x∈R





Domain of the equation: 2(8x+10))!=0

x∈R



We calculate fractions


(2x8/(2(2x-8)*2(8x+10)))+(-2x2/(2(2x-8)*2(8x+10)))=0



We calculate terms in parentheses: +(2x8/(2(2x-8)*2(8x+10))), so:

2x8/(2(2x-8)*2(8x+10))

We multiply all the terms by the denominator


2x8

We add all the numbers together, and all the variables

2x^8

We do not support expression: x^8

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