1/2(2x-7)-2x+4=3+2(x+2)

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Solution for 1/2(2x-7)-2x+4=3+2(x+2) equation: 



1/2(2x-7)-2x+4=3+2(x+2)

We move all terms to the left:

1/2(2x-7)-2x+4-(3+2(x+2))=0



Domain of the equation: 2(2x-7)!=0

x∈R



We add all the numbers together, and all the variables

-2x+1/2(2x-7)-(3+2(x+2))+4=0

We multiply all the terms by the denominator


-2x*2(2x-7)-((3+2(x+2)))*2(2x-7)+4*2(2x-7)+1=0



We calculate terms in parentheses: -((3+2(x+2)))*2(2x-7), so:

(3+2(x+2)))*2(2x-7



Wy multiply elements

-4x^2(2-((3+2(x+2)))*2(2x-7)+8x(2+1=0

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