1/2(2x+8)=2(x-2)

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Solution for 1/2(2x+8)=2(x-2) equation: 



1/2(2x+8)=2(x-2)

We move all terms to the left:

1/2(2x+8)-(2(x-2))=0



Domain of the equation: 2(2x+8)!=0

x∈R



We multiply all the terms by the denominator


-((2(x-2)))*2(2x+8)+1=0



We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), so:

(2(x-2)))*2(2x+8





We calculate terms in parentheses: -((2(x-2)))*2(2x+8), s

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