1/2(2x+3)+3/4=3/8(-3x-4)

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Solution for 1/2(2x+3)+3/4=3/8(-3x-4) equation: 



1/2(2x+3)+3/4=3/8(-3x-4)

We move all terms to the left:

1/2(2x+3)+3/4-(3/8(-3x-4))=0



Domain of the equation: 2(2x+3)!=0

x∈R





Domain of the equation: 8(-3x-4))!=0

x∈R



We calculate fractions


(32x(-)/(2(2x+3)*8(-3x-4))*4)+(-(3*2(2x+3)*4)/(2(2x+3)*8(-3x-4))*4)+(48x^22/(2(2x+3)*8(-3x-4))*4)=0



We calculate terms in parentheses: +(32x(-)/(2(2x+3)*8(-3x-4))*4), so:

32x(-)/(2(2x+3)*8(-3x-4))*4

We add all the numbers together, and all the variables

32x0/(2(2x+3)*8(-3x-4))*4

We multiply all the terms by the denominator


32x0

We add all the numbers together, and all the variables

32x

Back to the equation:

+(32x)





We calculate terms in parentheses: +(-(3*2(2x+3)*4)/(2(2x+3)*8(-3x-4))*4), so:

-(3*2(2x+3)*4)/(2(2x+3)*8(-3x-4))*4

We multiply all the terms by the denominator


-(3*2(2x+3)*4)



We calculate terms in parentheses: -(3*2(2x+3)*4), so:

3*2(2x+3)*4

Wy multiply elements

24x(2

Back to the equation:

-(24x(2)



Back to the equation:

+(-(24x2)





We calculate terms in parentheses: +(48x^22/(2(2x+3)*8(-3x-4))*4), so:

48x^22/(2(2x+3)*8(-3x-4))*4

We do not support expression: x^22

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