1/2(2x+10)-8=-7x+8x-3

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Solution for 1/2(2x+10)-8=-7x+8x-3 equation: 



1/2(2x+10)-8=-7x+8x-3

We move all terms to the left:

1/2(2x+10)-8-(-7x+8x-3)=0



Domain of the equation: 2(2x+10)!=0

x∈R



We add all the numbers together, and all the variables

1/2(2x+10)-(x-3)-8=0

We get rid of parentheses

1/2(2x+10)-x+3-8=0

We multiply all the terms by the denominator


-x*2(2x+10)+3*2(2x+10)-8*2(2x+10)+1=0

Wy multiply elements

-2x^2(2+6x(2-16x(2+1=0

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