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1/2(2x+10)(x+3)=63
We move all terms to the left:
1/2(2x+10)(x+3)-(63)=0
Domain of the equation: 2(2x+10)(x+3)!=0We multiply parentheses ..
x∈R
1/2(+2x^2+6x+10x+30)-63=0
We multiply all the terms by the denominator
-63*2(+2x^2+6x+10x+30)+1=0
Wy multiply elements
-126x(++1=0
We use the square of the difference formula
-126x(+1=0
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