1/2(2g-3)=4(g+1)

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Solution for 1/2(2g-3)=4(g+1) equation: 



1/2(2g-3)=4(g+1)

We move all terms to the left:

1/2(2g-3)-(4(g+1))=0



Domain of the equation: 2(2g-3)!=0

g∈R



We multiply all the terms by the denominator


-((4(g+1)))*2(2g-3)+1=0



We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), so:

(4(g+1)))*2(2g-3





We calculate terms in parentheses: -((4(g+1)))*2(2g-3), s

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