1/2(2b-2)=b-3

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Solution for 1/2(2b-2)=b-3 equation: 



1/2(2b-2)=b-3

We move all terms to the left:

1/2(2b-2)-(b-3)=0



Domain of the equation: 2(2b-2)!=0

b∈R



We get rid of parentheses

1/2(2b-2)-b+3=0

We multiply all the terms by the denominator


-b*2(2b-2)+3*2(2b-2)+1=0

Wy multiply elements

-2b^2(2+6b(2+1=0

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