1/2(28+2x)=5(x-2

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Solution for 1/2(28+2x)=5(x-2 equation: 



1/2(28+2x)=5(x-2

We move all terms to the left:

1/2(28+2x)-(5(x-2)=0



Domain of the equation: 2(28+2x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(2x+28)-(5(x-2)=0

We multiply all the terms by the denominator


-((5(x-2))*2(2x+28)+1=0

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