1/2(2-6x)-4(x+3/2=-(x-3)+4

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Solution for 1/2(2-6x)-4(x+3/2=-(x-3)+4 equation: 



1/2(2-6x)-4(x+3/2=-(x-3)+4

We move all terms to the left:

1/2(2-6x)-4(x+3/2-(-(x-3)+4)=0



Domain of the equation: 2(2-6x)!=0

x∈R





Domain of the equation: 2-(-(x-3)+4)!=0

We move all terms containing x to the left, all other terms to the right

-(-(x-3)+4)!=-2

x∈R



We add all the numbers together, and all the variables

1/2(-6x+2)-4(x+3/2-(-(x-3)+4)=0

We calculate fractions


(x-5)/(-23x+1)+(-4(x+3*2(-6x+2))/(-23x+1)=0



We calculate terms in parentheses: +(-4(x+3*2(-6x+2))/(-23x+1), so:

-4(x+3*2(-6x+2))/(-23x+1

We multiply all the terms by the denominator


-4(x+3*2(-6x+2))

Back to the equation:

+(-4(x+3*2(-6x+2)))



We multiply all the terms by the denominator


(x-5)+((-4(x+3*2(-6x+2))))*(-23x+1)=0



We calculate terms in parentheses: +((-4(x+3*2(-6x+2))))*(-23x+1), so:

(-4(x+3*2(-6x+2))))*(-23x+1

We add all the numbers together, and all the variables

-23x+(-4(x+3*2(-6x+2))))*(+1

Back to the equation:

+(-23x+(-4(x+3*2(-6x+2))))*(+1)



We add all the numbers together, and all the variables

(x-5)+(-23x+(-4(x+3*2(-6x+2))))*1=0

We get rid of parentheses

x+(-23x+(-4(x+3*2(-6x+2))))*1-5=0

We move all terms containing x to the left, all other terms to the right

x+(-23x+(-4(x+3*2(-6x+2))))*1=5

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