1/2(2-6x)-4(x+3-2)=-(x-3)+4

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Solution for 1/2(2-6x)-4(x+3-2)=-(x-3)+4 equation: 



1/2(2-6x)-4(x+3-2)=-(x-3)+4

We move all terms to the left:

1/2(2-6x)-4(x+3-2)-(-(x-3)+4)=0



Domain of the equation: 2(2-6x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-6x+2)-4(x+1)-(-(x-3)+4)=0

We multiply parentheses

1/2(-6x+2)-4x-(-(x-3)+4)-4=0

We multiply all the terms by the denominator


-4x*2(-6x+2)-((-(x-3)+4))*2(-6x+2)-4*2(-6x+2)+1=0



We calculate terms in parentheses: -((-(x-3)+4))*2(-6x+2), so:

(-(x-3)+4))*2(-6x+2

We add all the numbers together, and all the variables

-6x+(-(x-3)+4))*2(+2

Back to the equation:

-(-6x+(-(x-3)+4))*2(+2)



We add all the numbers together, and all the variables

-4x*2(-6x+2)-(-6x+(-(x-3)+4))*22-4*2(-6x+2)+1=0

Wy multiply elements

-8x^2(--(-6x+(-(x-3)+4))*22-8x(-+1=0

We use the square of the difference formula

-8x^2(+(-6x+(-(x-3)+4))*22-8x(-1=0

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