1/2(16x+8)-11=-1/3(18x-18)

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Solution for 1/2(16x+8)-11=-1/3(18x-18) equation: 



1/2(16x+8)-11=-1/3(18x-18)

We move all terms to the left:

1/2(16x+8)-11-(-1/3(18x-18))=0



Domain of the equation: 2(16x+8)!=0

x∈R





Domain of the equation: 3(18x-18))!=0

x∈R



We calculate fractions


(3x1/(2(16x+8)*3(18x-18)))+(-(-2x1)/(2(16x+8)*3(18x-18)))-11=0



We calculate terms in parentheses: +(3x1/(2(16x+8)*3(18x-18))), so:

3x1/(2(16x+8)*3(18x-18))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-(-2x1)/(2(16x+8)*3(18x-18))), so:

-(-2x1)/(2(16x+8)*3(18x-18))

We add all the numbers together, and all the variables

-(-2x)/(2(16x+8)*3(18x-18))

We multiply all the terms by the denominator


-(-2x)

We get rid of parentheses

2x

Back to the equation:

+(2x)



We add all the numbers together, and all the variables

5x-11=0

We move all terms containing x to the left, all other terms to the right

5x=11

x=11/5

x=2+1/5

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