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1/2(14x+12)-12=-2/5(15x-25)
We move all terms to the left:
1/2(14x+12)-12-(-2/5(15x-25))=0
Domain of the equation: 2(14x+12)!=0
x∈R
Domain of the equation: 5(15x-25))!=0We calculate fractions
x∈R
(5x1/(2(14x+12)*5(15x-25)))+(-(-4x1)/(2(14x+12)*5(15x-25)))-12=0
We calculate terms in parentheses: +(5x1/(2(14x+12)*5(15x-25))), so:
5x1/(2(14x+12)*5(15x-25))
We multiply all the terms by the denominator
5x1
We add all the numbers together, and all the variables
5x
Back to the equation:
+(5x)
We calculate terms in parentheses: +(-(-4x1)/(2(14x+12)*5(15x-25))), so:We add all the numbers together, and all the variables
-(-4x1)/(2(14x+12)*5(15x-25))
We add all the numbers together, and all the variables
-(-4x)/(2(14x+12)*5(15x-25))
We multiply all the terms by the denominator
-(-4x)
We get rid of parentheses
4x
Back to the equation:
+(4x)
9x-12=0
We move all terms containing x to the left, all other terms to the right
9x=12
x=12/9
x=1+1/3
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