1/2(12x+8)=1/4(12x+28)

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Solution for 1/2(12x+8)=1/4(12x+28) equation: 



1/2(12x+8)=1/4(12x+28)

We move all terms to the left:

1/2(12x+8)-(1/4(12x+28))=0



Domain of the equation: 2(12x+8)!=0

x∈R





Domain of the equation: 4(12x+28))!=0

x∈R



We calculate fractions


(4x1/(2(12x+8)*4(12x+28)))+(-2x1/(2(12x+8)*4(12x+28)))=0



We calculate terms in parentheses: +(4x1/(2(12x+8)*4(12x+28))), so:

4x1/(2(12x+8)*4(12x+28))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-2x1/(2(12x+8)*4(12x+28))), so:

-2x1/(2(12x+8)*4(12x+28))

We multiply all the terms by the denominator


-2x1

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

4x-2x=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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