1/2(12x+14)-16=-1/3(18x-6)

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Solution for 1/2(12x+14)-16=-1/3(18x-6) equation: 



1/2(12x+14)-16=-1/3(18x-6)

We move all terms to the left:

1/2(12x+14)-16-(-1/3(18x-6))=0



Domain of the equation: 2(12x+14)!=0

x∈R





Domain of the equation: 3(18x-6))!=0

x∈R



We calculate fractions


(3x1/(2(12x+14)*3(18x-6)))+(-(-2x1)/(2(12x+14)*3(18x-6)))-16=0



We calculate terms in parentheses: +(3x1/(2(12x+14)*3(18x-6))), so:

3x1/(2(12x+14)*3(18x-6))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-(-2x1)/(2(12x+14)*3(18x-6))), so:

-(-2x1)/(2(12x+14)*3(18x-6))

We add all the numbers together, and all the variables

-(-2x)/(2(12x+14)*3(18x-6))

We multiply all the terms by the denominator


-(-2x)

We get rid of parentheses

2x

Back to the equation:

+(2x)



We add all the numbers together, and all the variables

5x-16=0

We move all terms containing x to the left, all other terms to the right

5x=16

x=16/5

x=3+1/5

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