1/2(12-4x)=1/3(3-9x)

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Solution for 1/2(12-4x)=1/3(3-9x) equation:



1/2(12-4x)=1/3(3-9x)
We move all terms to the left:
1/2(12-4x)-(1/3(3-9x))=0
Domain of the equation: 2(12-4x)!=0
x∈R
Domain of the equation: 3(3-9x))!=0
x∈R
We add all the numbers together, and all the variables
1/2(-4x+12)-(1/3(-9x+3))=0
We calculate fractions
(3x(-)/(2(-4x+12)*3(-9x+3)))+(-2x0/(2(-4x+12)*3(-9x+3)))=0
We calculate terms in parentheses: +(3x(-)/(2(-4x+12)*3(-9x+3))), so:
3x(-)/(2(-4x+12)*3(-9x+3))
We add all the numbers together, and all the variables
3x0/(2(-4x+12)*3(-9x+3))
We multiply all the terms by the denominator
3x0
We add all the numbers together, and all the variables
3x
Back to the equation:
+(3x)
We calculate terms in parentheses: +(-2x0/(2(-4x+12)*3(-9x+3))), so:
-2x0/(2(-4x+12)*3(-9x+3))
We multiply all the terms by the denominator
-2x0
We add all the numbers together, and all the variables
-2x
Back to the equation:
+(-2x)
We get rid of parentheses
3x-2x=0
We add all the numbers together, and all the variables
x=0

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