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1/2(12-2x)=5x+2(x-7)
We move all terms to the left:
1/2(12-2x)-(5x+2(x-7))=0
Domain of the equation: 2(12-2x)!=0We add all the numbers together, and all the variables
x∈R
1/2(-2x+12)-(5x+2(x-7))=0
We multiply all the terms by the denominator
-((5x+2(x-7)))*2(-2x+12)+1=0
We calculate terms in parentheses: -((5x+2(x-7)))*2(-2x+12), so:We add all the numbers together, and all the variables
(5x+2(x-7)))*2(-2x+12
We add all the numbers together, and all the variables
-2x+(5x+2(x-7)))*2(+12
Back to the equation:
-(-2x+(5x+2(x-7)))*2(+12)
-(-2x+(5x+2(x-7)))*212+1=0
We move all terms containing x to the left, all other terms to the right
-(-2x+(5x+2(x-7)))*212=-1
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