1/2(10y+10)=1/3(15y+30)

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Solution for 1/2(10y+10)=1/3(15y+30) equation:



1/2(10y+10)=1/3(15y+30)
We move all terms to the left:
1/2(10y+10)-(1/3(15y+30))=0
Domain of the equation: 2(10y+10)!=0
y∈R
Domain of the equation: 3(15y+30))!=0
y∈R
We calculate fractions
(3y1/(2(10y+10)*3(15y+30)))+(-2y1/(2(10y+10)*3(15y+30)))=0
We calculate terms in parentheses: +(3y1/(2(10y+10)*3(15y+30))), so:
3y1/(2(10y+10)*3(15y+30))
We multiply all the terms by the denominator
3y1
We add all the numbers together, and all the variables
3y
Back to the equation:
+(3y)
We calculate terms in parentheses: +(-2y1/(2(10y+10)*3(15y+30))), so:
-2y1/(2(10y+10)*3(15y+30))
We multiply all the terms by the denominator
-2y1
We add all the numbers together, and all the variables
-2y
Back to the equation:
+(-2y)
We get rid of parentheses
3y-2y=0
We add all the numbers together, and all the variables
y=0

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