1/2(10x-5x)=1/3(6-4x)

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Solution for 1/2(10x-5x)=1/3(6-4x) equation: 



1/2(10x-5x)=1/3(6-4x)

We move all terms to the left:

1/2(10x-5x)-(1/3(6-4x))=0



Domain of the equation: 2(10x-5x)!=0

x∈R





Domain of the equation: 3(6-4x))!=0

x∈R



We add all the numbers together, and all the variables

1/2(+5x)-(1/3(-4x+6))=0

We calculate fractions


(3x(-)/(2(+5x)*3(-4x+6)))+(-2x0/(2(+5x)*3(-4x+6)))=0



We calculate terms in parentheses: +(3x(-)/(2(+5x)*3(-4x+6))), so:

3x(-)/(2(+5x)*3(-4x+6))

We add all the numbers together, and all the variables

3x0/(2(+5x)*3(-4x+6))

We multiply all the terms by the denominator


3x0

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-2x0/(2(+5x)*3(-4x+6))), so:

-2x0/(2(+5x)*3(-4x+6))

We multiply all the terms by the denominator


-2x0

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

3x-2x=0

We add all the numbers together, and all the variables

x=0

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