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1/2(10c-8)=5+8
We move all terms to the left:
1/2(10c-8)-(5+8)=0
Domain of the equation: 2(10c-8)!=0We add all the numbers together, and all the variables
c∈R
1/2(10c-8)-13=0
We multiply all the terms by the denominator
-13*2(10c-8)+1=0
Wy multiply elements
-26c(1+1=0
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