1/2(-8x-8)=-40+5x

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Solution for 1/2(-8x-8)=-40+5x equation: 



1/2(-8x-8)=-40+5x

We move all terms to the left:

1/2(-8x-8)-(-40+5x)=0



Domain of the equation: 2(-8x-8)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-8x-8)-(5x-40)=0

We get rid of parentheses

1/2(-8x-8)-5x+40=0

We multiply all the terms by the denominator


-5x*2(-8x-8)+40*2(-8x-8)+1=0

Wy multiply elements

-10x^2(-+80x(-+1=0

We use the square of the difference formula

-10x^2(-80x(-1=0

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