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1/18x+2/3=5/6x
We move all terms to the left:
1/18x+2/3-(5/6x)=0
Domain of the equation: 18x!=0
x!=0/18
x!=0
x∈R
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/18x-(+5/6x)+2/3=0
We get rid of parentheses
1/18x-5/6x+2/3=0
We calculate fractions
1296x^2/972x^2+54x/972x^2+(-810x)/972x^2=0
We multiply all the terms by the denominator
1296x^2+54x+(-810x)=0
We get rid of parentheses
1296x^2+54x-810x=0
We add all the numbers together, and all the variables
1296x^2-756x=0
a = 1296; b = -756; c = 0;
Δ = b2-4ac
Δ = -7562-4·1296·0
Δ = 571536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{571536}=756$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-756)-756}{2*1296}=\frac{0}{2592} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-756)+756}{2*1296}=\frac{1512}{2592} =7/12 $
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