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1/16x+1/12x=1
We move all terms to the left:
1/16x+1/12x-(1)=0
Domain of the equation: 16x!=0
x!=0/16
x!=0
x∈R
Domain of the equation: 12x!=0We calculate fractions
x!=0/12
x!=0
x∈R
12x/192x^2+16x/192x^2-1=0
We multiply all the terms by the denominator
12x+16x-1*192x^2=0
We add all the numbers together, and all the variables
28x-1*192x^2=0
Wy multiply elements
-192x^2+28x=0
a = -192; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-192)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-192}=\frac{-56}{-384} =7/48 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-192}=\frac{0}{-384} =0 $
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