1/14(x+12)=1/22(x+10)

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Solution for 1/14(x+12)=1/22(x+10) equation: 



1/14(x+12)=1/22(x+10)

We move all terms to the left:

1/14(x+12)-(1/22(x+10))=0



Domain of the equation: 14(x+12)!=0

x∈R





Domain of the equation: 22(x+10))!=0

x∈R



We calculate fractions


(22xx/(14(x+12)*22(x+10)))+(-14xx/(14(x+12)*22(x+10)))=0



We calculate terms in parentheses: +(22xx/(14(x+12)*22(x+10))), so:

22xx/(14(x+12)*22(x+10))

We multiply all the terms by the denominator


22xx

Back to the equation:

+(22xx)





We calculate terms in parentheses: +(-14xx/(14(x+12)*22(x+10))), so:

-14xx/(14(x+12)*22(x+10))

We multiply all the terms by the denominator


-14xx

Back to the equation:

+(-14xx)



We get rid of parentheses

22xx-14xx=0

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