1/12x+1/10x=36

Solution for 1/12x+1/10x=36 equation:

1/12x+1/10x=36

We move all terms to the left:

1/12x+1/10x-(36)=0


Domain of the equation: 12x!=0

x!=0/12

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We calculate fractions


10x/120x^2+12x/120x^2-36=0

We multiply all the terms by the denominator


10x+12x-36*120x^2=0

We add all the numbers together, and all the variables

22x-36*120x^2=0

Wy multiply elements

-4320x^2+22x=0

a = -4320; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-4320)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-4320}=\frac{-44}{-8640}
=11/2160
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-4320}=\frac{0}{-8640}
=0
$