1/12(t+1)=1/9(t+2)

Solution for 1/12(t+1)=1/9(t+2) equation:

1/12(t+1)=1/9(t+2)

We move all terms to the left:

1/12(t+1)-(1/9(t+2))=0


Domain of the equation: 12(t+1)!=0

t∈R



Domain of the equation: 9(t+2))!=0

t∈R


We calculate fractions


(9tt/(12(t+1)*9(t+2)))+(-12tt/(12(t+1)*9(t+2)))=0


We calculate terms in parentheses: +(9tt/(12(t+1)*9(t+2))), so:

9tt/(12(t+1)*9(t+2))

We multiply all the terms by the denominator


9tt

Back to the equation:

+(9tt)



We calculate terms in parentheses: +(-12tt/(12(t+1)*9(t+2))), so:

-12tt/(12(t+1)*9(t+2))

We multiply all the terms by the denominator


-12tt

Back to the equation:

+(-12tt)


We get rid of parentheses

9tt-12tt=0