1/12(4m+57)=1/4(2m+11)

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Solution for 1/12(4m+57)=1/4(2m+11) equation: 



1/12(4m+57)=1/4(2m+11)

We move all terms to the left:

1/12(4m+57)-(1/4(2m+11))=0



Domain of the equation: 12(4m+57)!=0

m∈R





Domain of the equation: 4(2m+11))!=0

m∈R



We calculate fractions


(4m2/(12(4m+57)*4(2m+11)))+(-12m4/(12(4m+57)*4(2m+11)))=0



We calculate terms in parentheses: +(4m2/(12(4m+57)*4(2m+11))), so:

4m2/(12(4m+57)*4(2m+11))

We multiply all the terms by the denominator


4m2

We add all the numbers together, and all the variables

4m^2

Back to the equation:

+(4m^2)





We calculate terms in parentheses: +(-12m4/(12(4m+57)*4(2m+11))), so:

-12m4/(12(4m+57)*4(2m+11))

We multiply all the terms by the denominator


-12m4

We add all the numbers together, and all the variables

-12m^4

We do not support empression: m^4

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