1/12(48+24b=2(17-4b)

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Solution for 1/12(48+24b=2(17-4b) equation: 



1/12(48+24b=2(17-4b)

We move all terms to the left:

1/12(48+24b-(2(17-4b))=0



Domain of the equation: 12(48+24b-(2(17-4b))!=0

b∈R



We add all the numbers together, and all the variables

1/12(48+24b-(2(-4b+17))=0

We multiply all the terms by the denominator


1!=0

There is no solution for this equation

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