1/10(x-62)=1+x

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Solution for 1/10(x-62)=1+x equation: 



1/10(x-62)=1+x

We move all terms to the left:

1/10(x-62)-(1+x)=0



Domain of the equation: 10(x-62)!=0

x∈R



We add all the numbers together, and all the variables

1/10(x-62)-(x+1)=0

We get rid of parentheses

1/10(x-62)-x-1=0

We multiply all the terms by the denominator


-x*10(x-62)-1*10(x-62)+1=0

Wy multiply elements

-10x^2(x-10x(x+1=0

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