1/10(x+35)=2(3-x)

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Solution for 1/10(x+35)=2(3-x) equation: 



1/10(x+35)=2(3-x)

We move all terms to the left:

1/10(x+35)-(2(3-x))=0



Domain of the equation: 10(x+35)!=0

x∈R



We add all the numbers together, and all the variables

1/10(x+35)-(2(-1x+3))=0

We multiply all the terms by the denominator


-((2(-1x+3)))*10(x+35)+1=0



We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)))*10(x+35), so:

(2(-1x+3)))*10(x+35





We calculate terms in parentheses: -((2(-1x+3)

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