1/10(i+50)=-3i-13+4i

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Solution for 1/10(i+50)=-3i-13+4i equation: 



1/10(i+50)=-3i-13+4i

We move all terms to the left:

1/10(i+50)-(-3i-13+4i)=0



Domain of the equation: 10(i+50)!=0

i∈R



We add all the numbers together, and all the variables

1/10(i+50)-(i-13)=0

We get rid of parentheses

1/10(i+50)-i+13=0

We multiply all the terms by the denominator


-i*10(i+50)+13*10(i+50)+1=0

Wy multiply elements

-10i^2(i+130i(i+1=0

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