1/10(a+2)=1/2(2-a)

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Solution for 1/10(a+2)=1/2(2-a) equation: 



1/10(a+2)=1/2(2-a)

We move all terms to the left:

1/10(a+2)-(1/2(2-a))=0



Domain of the equation: 10(a+2)!=0

a∈R





Domain of the equation: 2(2-a))!=0

a∈R



We add all the numbers together, and all the variables

1/10(a+2)-(1/2(-1a+2))=0

We calculate fractions


(2a(-)/(10(a+2)*2(-1a+2)))+(-10aa/(10(a+2)*2(-1a+2)))=0



We calculate terms in parentheses: +(2a(-)/(10(a+2)*2(-1a+2))), so:

2a(-)/(10(a+2)*2(-1a+2))

We add all the numbers together, and all the variables

2a0/(10(a+2)*2(-1a+2))

We multiply all the terms by the denominator


2a0

We add all the numbers together, and all the variables

2a

Back to the equation:

+(2a)





We calculate terms in parentheses: +(-10aa/(10(a+2)*2(-1a+2))), so:

-10aa/(10(a+2)*2(-1a+2))

We multiply all the terms by the denominator


-10aa

Back to the equation:

+(-10aa)



We get rid of parentheses

2a-10aa=0

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