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1/)x+5=19-1/2x
We move all terms to the left:
1/)x+5-(19-1/2x)=0
Domain of the equation: )x+5-(19!=0
We move all terms containing x to the left, all other terms to the right
)x-(19!=-5
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/)x+5-(-1/2x+19)=0
We add all the numbers together, and all the variables
1/)x+5-(-1/2x=0
We calculate fractions
2x/()x-(*2x+5)+(-1*)x-()/()x-(*2x+5)+5=0
We add all the numbers together, and all the variables
2x/()x-(*2x+5)+0x-()/()x-(*2x+5)+5=0
We add all the numbers together, and all the variables
x+2x/()x-(*2x+5)-()/()x-(*2x+5)+5=0
We get rid of parentheses
x+2x/()x-*2x-()/()x-*2x-5-5+5=0
We multiply all the terms by the denominator
x*()x+2x-(*2x)*()x-(*2x)*()x-5*()x-5*()x+5*()x-()=0
We add all the numbers together, and all the variables
x*()x+2x-(+*2x)*()x-(+*2x)*()x-5*()x-5*()x+5*()x-()=0
We add all the numbers together, and all the variables
2x+x*()x-(+*2x)*()x-(+*2x)*()x-5*()x-5*()x+5*()x=0
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