1/(z-1)=2/(z+1)

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Solution for 1/(z-1)=2/(z+1) equation: 


D( z )

z-1 = 0

z+1 = 0

z-1 = 0

z-1 = 0

z-1 = 0 // + 1

z = 1

z+1 = 0

z+1 = 0

z+1 = 0 // - 1

z = -1

z in (-oo:-1) U (-1:1) U (1:+oo)

1/(z-1) = 2/(z+1) // - 2/(z+1)

1/(z-1)-(2/(z+1)) = 0

1/(z-1)-2*(z+1)^-1 = 0

1/(z-1)-2/(z+1) = 0

(1*(z+1))/((z-1)*(z+1))+(-2*(z-1))/((z-1)*(z+1)) = 0

1*(z+1)-2*(z-1) = 0

3-z = 0

(3-z)/((z-1)*(z+1)) = 0

(3-z)/((z-1)*(z+1)) = 0 // * (z-1)*(z+1)

3-z = 0

3-z = 0 // - 3

-z = -3 // * -1

z = 3

z = 3

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