1/(x-1)+2/(x+1)=2

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Solution for 1/(x-1)+2/(x+1)=2 equation: 



1/(x-1)+2/(x+1)=2

We move all terms to the left:

1/(x-1)+2/(x+1)-(2)=0



Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R





Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R



We calculate fractions


(1*(x+1))/((x-1)*(x+1))+(2x-2)/((x-1)*(x+1))-2=0



We calculate terms in parentheses: +(1*(x+1))/((x-1)*(x+1)), so:

1*(x+1))/((x-1)*(x+1)

We multiply all the terms by the denominator


1*(x+1))

Back to the equation:

+(1*(x+1)))





We calculate terms in parentheses: +(2x-2)/((x-1)*(x+1)), so:

2x-2)/((x-1)*(x+1)

We multiply all the terms by the denominator


2x*((x-1)*(x+1)-2)

Back to the equation:

+(2x*((x-1)*(x+1)-2))

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