1/(x-1)+1/(x-2)+1/(x-3)=0

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Solution for 1/(x-1)+1/(x-2)+1/(x-3)=0 equation: 



1/(x-1)+1/(x-2)+1/(x-3)=0



Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R





Domain of the equation: (x-2)!=0

We move all terms containing x to the left, all other terms to the right

x!=2

x∈R





Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R



We calculate fractions


(1*(x-2)*(x-3))/((x-1)*(x-2)*(x-3))+(1*(x-1)*(x-3))/((x-1)*(x-2)*(x-3))+(1*(x-1)*(x-2))/((x-1)*(x-2)*(x-3))=0



We calculate terms in parentheses: +(1*(x-2)*(x-3))/((x-1)*(x-2)*(x-3)), so:

1*(x-2)*(x-3))/((x-1)*(x-2)*(x-3)

We multiply all the terms by the denominator


1*(x-2)*(x-3))

Back to the equation:

+(1*(x-2)*(x-3)))





We calculate terms in parentheses: +(1*(x-1)*(x-3))/((x-1)*(x-2)*(x-3)), so:

1*(x-1)*(x-3))/((x-1)*(x-2)*(x-3)

We multiply all the terms by the denominator


1*(x-1)*(x-3))

Back to the equation:

+(1*(x-1)*(x-3)))





We calculate terms in parentheses: +(1*(x-1)*(x-2))/((x-1)*(x-2)*(x-3)), so:

1*(x-1)*(x-2))/((x-1)*(x-2)*(x-3)

We multiply all the terms by the denominator


1*(x-1)*(x-2))

Back to the equation:

+(1*(x-1)*(x-2)))



We add all the numbers together, and all the variables

(1*(x-2)*(x-3)))+(1*(x-1)*(x-3)))+(1*(x-1)*(x=0

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