1/(x+2)+1/(x+4)=0

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Solution for 1/(x+2)+1/(x+4)=0 equation: 



1/(x+2)+1/(x+4)=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R



We calculate fractions


(1*(x+4))/((x+2)*(x+4))+(1*(x+2))/((x+2)*(x+4))=0



We calculate terms in parentheses: +(1*(x+4))/((x+2)*(x+4)), so:

1*(x+4))/((x+2)*(x+4)

We multiply all the terms by the denominator


1*(x+4))

Back to the equation:

+(1*(x+4)))





We calculate terms in parentheses: +(1*(x+2))/((x+2)*(x+4)), so:

1*(x+2))/((x+2)*(x+4)

We multiply all the terms by the denominator


1*(x+2))

Back to the equation:

+(1*(x+2)))





We calculate terms in parentheses: +(1*(x+4)))+(1*(x+2))), so:

1*(x+4)))+(1*(x+2))

We add all the numbers together, and all the variables

1*(x+4)))+(1*(x

Back to the equation:

+(1*(x+4)))+(1*(x)

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