1/(p-2)=(1/3)

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Solution for 1/(p-2)=(1/3) equation: 


D( p )

p-2 = 0

p-2 = 0

p-2 = 0

p-2 = 0 // + 2

p = 2

p in (-oo:2) U (2:+oo)

1/(p-2) = 1/3 // - 1/3

1/(p-2)-(1/3) = 0

1/(p-2)-1/3 = 0

(1*3)/(3*(p-2))+(-1*(p-2))/(3*(p-2)) = 0

1*3-1*(p-2) = 0

5-p = 0

(5-p)/(3*(p-2)) = 0

(5-p)/(3*(p-2)) = 0 // * 3*(p-2)

5-p = 0

5-p = 0 // - 5

-p = -5 // * -1

p = 5

p = 5

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