1/(n-3)(n-2)=20

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Solution for 1/(n-3)(n-2)=20 equation: 


D( n )

n-3 = 0

n-3 = 0

n-3 = 0

n-3 = 0 // + 3

n = 3

n in (-oo:3) U (3:+oo)

(1/(n-3))*(n-2) = 20 // - 20

(1/(n-3))*(n-2)-20 = 0

(1*(n-2))/(n-3)-20 = 0

(1*(n-2))/(n-3)+(-20*(n-3))/(n-3) = 0

1*(n-2)-20*(n-3) = 0

58-19*n = 0

(58-19*n)/(n-3) = 0

(58-19*n)/(n-3) = 0 // * n-3

58-19*n = 0

58-19*n = 0 // - 58

-19*n = -58 // : -19

n = -58/(-19)

n = 58/19

n = 58/19

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