1/(X+1)=1/X+1+2

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Solution for 1/(X+1)=1/X+1+2 equation:


D( X )

X = 0

X+1 = 0

X = 0

X = 0

X+1 = 0

X+1 = 0

X+1 = 0 // - 1

X = -1

X in (-oo:-1) U (-1:0) U (0:+oo)

1/(X+1) = 1/X+1+2 // - 1/X+1+2

1/(X+1)-(1/X)-2-1 = 0

1/(X+1)-X^-1-2-1 = 0

1/(X+1)-1/X-2-1 = 0

(1*X)/(X*(X+1))+(-1*(X+1))/(X*(X+1))+(-2*X*(X+1))/(X*(X+1))+(-1*X*(X+1))/(X*(X+1)) = 0

1*X-1*(X+1)-2*X*(X+1)-1*X*(X+1) = 0

-2*X^2-X^2-2*X-X-1 = 0

-3*X^2-3*X-1 = 0

-3*X^2-3*X-1 = 0

-1*(3*X^2+3*X+1) = 0

3*X^2+3*X+1 = 0

DELTA = 3^2-(1*3*4)

DELTA = -3

DELTA < 0

-1 = 0

-1/(X*(X+1)) = 0

-1/(X*(X+1)) = 0 // * X*(X+1)

-1 = 0

X belongs to the empty set

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