1/(5-x)=1/8x

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Solution for 1/(5-x)=1/8x equation: 



1/(5-x)=1/8x

We move all terms to the left:

1/(5-x)-(1/8x)=0



Domain of the equation: (5-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-5

x!=-5/-1

x!=+5

x∈R





Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/(-1x+5)-(+1/8x)=0

We get rid of parentheses

1/(-1x+5)-1/8x=0

We calculate fractions


8x/(-8x^2+40x)+(-1*(-1x+5))/(-8x^2+40x)=0



We calculate terms in parentheses: +(-1*(-1x+5))/(-8x^2+40x), so:

-1*(-1x+5))/(-8x^2+40x

determiningTheFunctionDomain
-8x^2-1*(-1x+5))/(+40x

We add all the numbers together, and all the variables

-8x^2+40x-1*(-1x+5))/(

We multiply all the terms by the denominator


-8x^2*(+40x*(-1*(-1x+5))

Back to the equation:

+(-8x^2*(+40x*(-1*(-1x+5)))



We multiply all the terms by the denominator


((-8x^2*(+40x*(-1*(-1x+5))))*(-8x^2+40x)+8x=0

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