1/(4x)=(3)/(2x-6)

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Solution for 1/(4x)=(3)/(2x-6) equation: 



1/(4x)=(3)/(2x-6)

We move all terms to the left:

1/(4x)-((3)/(2x-6))=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: (2x-6))!=0

x∈R



We calculate fractions


-16x^2)+(-(3*4x)/(-16x^2)+(1*(2x-6)))/(=0

We add all the numbers together, and all the variables

-16x^2)+(-(+3*4x)/(-16x^2)+(1*(2x-6)))/(=0

We calculate fractions


-16x^2)+(+(-(+3*4x)*()/((-16x^2)*()+(-16x^2)+(1*(2x-6)))*()/((-16x^2)*()=0



We calculate terms in parentheses: +(-(+3*4x)*()/((-16x^2)*()+(-16x^2)+(1*(2x-6)))*()/((-16x^2)*(), so:

-(+3*4x)*()/((-16x^2)*()+(-16x^2)+(1*(2x-6)))*()/((-16x^2)*(

We can not solve this equation

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