1/(3x)-2x=4

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Solution for 1/(3x)-2x=4 equation:


D( x )

3*x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:0) U (0:+oo)

1/(3*x)-(2*x) = 4 // - 4

1/(3*x)-(2*x)-4 = 0

1/(3*x)-2*x-4 = 0

1/3*x^-1-2*x^1-4*x^0 = 0

(1/3*x^0-2*x^2-4*x^1)/(x^1) = 0 // * x^2

x^1*(1/3*x^0-2*x^2-4*x^1) = 0

x^1

1/3-2*x^2-4*x = 0

1/3-2*x^2-4*x = 0

DELTA = (-4)^2-(-2*4*(1/3))

DELTA = 56/3

DELTA > 0

x = ((56/3)^(1/2)+4)/(-2*2) or x = (4-(56/3)^(1/2))/(-2*2)

x = ((56/3)^(1/2)+4)/(-4) or x = (4-(56/3)^(1/2))/(-4)

x in { ((56/3)^(1/2)+4)/(-4), (4-(56/3)^(1/2))/(-4)}

x in { ((56/3)^(1/2)+4)/(-4), (4-(56/3)^(1/2))/(-4) }

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