1/(3-4j)=0.12+0.16j

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Solution for 1/(3-4j)=0.12+0.16j equation: 



1/(3-4j)=0.12+0.16j

We move all terms to the left:

1/(3-4j)-(0.12+0.16j)=0



Domain of the equation: (3-4j)!=0

We move all terms containing j to the left, all other terms to the right

-4j!=-3

j!=-3/-4

j!=3/4

j∈R



We add all the numbers together, and all the variables

1/(-4j+3)-(0.16j+0.12)=0

We get rid of parentheses

1/(-4j+3)-0.16j-0.12=0

We multiply all the terms by the denominator


-(0.16j)*(-4j+3)-(0.12)*(-4j+3)+1=0

We add all the numbers together, and all the variables

-(+0.16j)*(-4j+3)-(0.12)*(-4j+3)+1=0

We move all terms containing j to the left, all other terms to the right

-(+0.16j)*(-4j+3)-(0.12)*(-4j+3)=-1

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