1/(2x+3)=7/(x-4)

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Solution for 1/(2x+3)=7/(x-4) equation: 


D( x )

x-4 = 0

2*x+3 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0 // - 3

2*x = -3 // : 2

x = -3/2

x in (-oo:-3/2) U (-3/2:4) U (4:+oo)

1/(2*x+3) = 7/(x-4) // - 7/(x-4)

1/(2*x+3)-(7/(x-4)) = 0

1/(2*x+3)-7*(x-4)^-1 = 0

1/(2*x+3)-7/(x-4) = 0

(1*(x-4))/((2*x+3)*(x-4))+(-7*(2*x+3))/((2*x+3)*(x-4)) = 0

1*(x-4)-7*(2*x+3) = 0

-13*x-25 = 0

(-13*x-25)/((2*x+3)*(x-4)) = 0

(-13*x-25)/((2*x+3)*(x-4)) = 0 // * (2*x+3)*(x-4)

-13*x-25 = 0

-13*x-25 = 0 // + 25

-13*x = 25 // : -13

x = 25/(-13)

x = -25/13

x = -25/13

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