1/(2x+1)+1/(3x-1)=0

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Solution for 1/(2x+1)+1/(3x-1)=0 equation: 



1/(2x+1)+1/(3x-1)=0



Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R





Domain of the equation: (3x-1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=1

x!=1/3

x!=1/3

x∈R



We calculate fractions


(1*(3x-1))/((2x+1)*(3x-1))+(1*(2x+1))/((2x+1)*(3x-1))=0



We calculate terms in parentheses: +(1*(3x-1))/((2x+1)*(3x-1)), so:

1*(3x-1))/((2x+1)*(3x-1)

We multiply all the terms by the denominator


1*(3x-1))

Back to the equation:

+(1*(3x-1)))





We calculate terms in parentheses: +(1*(2x+1))/((2x+1)*(3x-1)), so:

1*(2x+1))/((2x+1)*(3x-1)

We multiply all the terms by the denominator


1*(2x+1))

Back to the equation:

+(1*(2x+1)))





We calculate terms in parentheses: +(1*(3x-1)))+(1*(2x+1))), so:

1*(3x-1)))+(1*(2x+1))

We add all the numbers together, and all the variables

1*(3x-1)))+(1*(2x

Back to the equation:

+(1*(3x-1)))+(1*(2x)

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